100x^2-3=20x

Solution for 100x^2-3=20x equation:

100x^2-3=20x

We move all terms to the left:

100x^2-3-(20x)=0

a = 100; b = -20; c = -3;
Δ = b2-4ac
Δ = -202-4·100·(-3)
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1600}=40$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-40}{2*100}=\frac{-20}{200}
=-1/10
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+40}{2*100}=\frac{60}{200}
=3/10
$